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I store the last value ( 687) in the cell J2.

Similarly, it should be converted to a number, so the final formula is: =NUMBERVALUE(MID(B2 F2+2 G2-F2-3) ".") Because it starts in the middle of the string, it’s best to use the MID function: =MID(B2 F2+2 G2-F2-3).

I store the second value ( 7.4) in the cell I2.

Finally, the cell H2 should contain this function: =NUMBERVALUE(LEFT(B2 F2-2) ".") Its first parameter is the string to be converted to a number, and the second parameter is the decimal point character.

To do so, we have to convert string to a number, e.g. Note that the result is a string, not a number, so it cannot be used i.a. Because it starts from the beginning of the string, it’s best to use the LEFT function: =LEFT(B2 F2-2). I store the first value ( 17.6) in the cell H2.To find a second or next the same character or substring, just start looking after the position of the previous occurrence (the last parameter): =FIND("|" B2 F2+1) I store the position of the second | character in the cell G2.I store the position of the first | character in the cell F2: =FIND("|" B2).First, we need to find positions of the two | characters, and then copy the text between them using simple functions:Įxcel uses, instead of for separating functions’ parameters for the US locale. How to extract the three values from it? One of the simplest methods is treating the | characters as delimiters. It contains the following string: 17.6 | 7.4 | 687. The correct way is: select the F column by clicking the column header, right-click the A column and select Paste Special, then Values or Text:įinally, I dropped the F column by right-clicking it and selecting Delete. Note that it’s not enough to copy the column F onto A, because there are formulas in the former column – moreover, they are dependent on the latter column. The last step is overwriting the column A with values from column F.

Then I used the fill feature to copy the formula onto other rows: I put that formula into the first available cell in the second row: F2. sometimes it’s possible to simply provide any larger number, e.g.the general formula is: LEN(A2) - starting position + 1.It will be equal to the length of the original text minus the 13 characters we want to be removed: the length of the fragment: unfortunately we can’t just ask for all text until the end without providing the length.from which character the fragment should start: it will be 14 (ignore the first 13 characters and start from the 14th).We have to use a function that will take a fragment of a string: MID. Apparently, this is a simple task, because the text to be removed has always the same length: 4 characters of “pick”, 1 for space, 7 characters of the hash and again 1 for space 13 characters in total.